fetch-tweet

Compare original and translation side by side

🇺🇸

Original

English

🇨🇳

Translation

Chinese

Fetch Tweet

获取推文

You fetch tweet content using the fxtwitter API, which returns structured JSON without requiring JavaScript rendering or authentication.

你可以使用fxtwitter API获取推文内容，该API会返回结构化JSON数据，无需JavaScript渲染或身份验证。

Why fxtwitter

为何选择fxtwitter

X/Twitter requires JavaScript to render tweets.

WebFetch

x.com

returns an empty shell. The fxtwitter API (

api.fxtwitter.com

) serves the same tweet data as plain JSON — no auth, no JS, no rate-limit friction for reasonable use.

X/Twitter需要借助JavaScript来渲染推文。在x.com上使用

WebFetch

只会返回空的页面框架。而fxtwitter API（

api.fxtwitter.com

）会以纯JSON格式提供相同的推文数据——无需身份验证、无需JavaScript，合理使用情况下也不会有速率限制问题。

URL Conversion

URL转换

Given any tweet URL, convert it to the fxtwitter API endpoint:

Input URL pattern	API URL
`https://x.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`
`https://twitter.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`
`https://fxtwitter.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`
`https://vxtwitter.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`

Extract the

<user>

and

<id>

from the input URL, then construct

https://api.fxtwitter.com/<user>/status/<id>

对于任意推文URL，可将其转换为fxtwitter API端点：

输入URL格式	API地址
`https://x.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`
`https://twitter.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`
`https://fxtwitter.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`
`https://vxtwitter.com/<user>/status/<id>`	`https://api.fxtwitter.com/<user>/status/<id>`

从输入URL中提取

<user>

和

<id>

，然后构造

https://api.fxtwitter.com/<user>/status/<id>

。

How to Fetch

如何获取数据

Use

WebFetch

with the converted API URL:

WebFetch(url: "https://api.fxtwitter.com/<user>/status/<id>", prompt: "Extract the tweet JSON. Return: author name, handle, tweet text, date, media URLs (if any), likes, retweets, replies, views.")

使用

WebFetch

调用转换后的API地址：

WebFetch(url: "https://api.fxtwitter.com/<user>/status/<id>", prompt: "Extract the tweet JSON. Return: author name, handle, tweet text, date, media URLs (if any), likes, retweets, replies, views.")

Response Structure

响应结构

The fxtwitter API returns JSON with this structure:

json

{
  "code": 200,
  "message": "OK",
  "tweet": {
    "url": "https://x.com/user/status/123",
    "text": "The tweet content...",
    "author": {
      "name": "Display Name",
      "screen_name": "handle"
    },
    "created_at": "Thu Jan 30 12:00:00 +0000 2026",
    "likes": 1000,
    "retweets": 500,
    "replies": 200,
    "views": 50000,
    "media": {
      "photos": [...],
      "videos": [...]
    }
  }
}

fxtwitter API返回的JSON结构如下：

json

{
  "code": 200,
  "message": "OK",
  "tweet": {
    "url": "https://x.com/user/status/123",
    "text": "The tweet content...",
    "author": {
      "name": "Display Name",
      "screen_name": "handle"
    },
    "created_at": "Thu Jan 30 12:00:00 +0000 2026",
    "likes": 1000,
    "retweets": 500,
    "replies": 200,
    "views": 50000,
    "media": {
      "photos": [...],
      "videos": [...]
    }
  }
}

Usage Pattern

使用流程

When you receive a tweet URL (x.com, twitter.com, fxtwitter.com, or vxtwitter.com):

Parse the URL to extract username and tweet ID

Convert to

https://api.fxtwitter.com/<user>/status/<id>

Fetch using
```
WebFetch
```
with the API URL
Present the tweet content in a readable format:

**Author Name** (@handle) — Date

"Tweet text here"

Engagement: X views, Y likes, Z retweets, W replies

If the tweet contains media (photos/videos), include the URLs.

当你收到推文URL（x.com、twitter.com、fxtwitter.com或vxtwitter.com）时：

解析URL以提取用户名和推文ID

转换为

https://api.fxtwitter.com/<user>/status/<id>

格式

获取：使用
```
WebFetch
```
调用转换后的API地址
展示：以易读格式呈现推文内容：

**作者名称** (@用户名) — 发布日期

"推文文本内容"

互动数据：X次浏览，Y个点赞，Z次转发，W条回复

如果推文包含媒体内容（图片/视频），请附上对应的链接。

Error Handling

错误处理

If fxtwitter returns a non-200 status, the tweet may have been deleted or the account suspended
If the URL doesn't match any known tweet URL pattern, ask the user for a valid tweet link

如果fxtwitter返回非200状态码，说明推文可能已被删除或账号已被封禁
如果URL不符合任何已知的推文URL格式，请要求用户提供有效的推文链接